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27x^2+8x-35=0
a = 27; b = 8; c = -35;
Δ = b2-4ac
Δ = 82-4·27·(-35)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-62}{2*27}=\frac{-70}{54} =-1+8/27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+62}{2*27}=\frac{54}{54} =1 $
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